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ksushavischnev
@ksushavischnev
October 2021
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trserg
Verified answer
2NaOH + CuSO4 = Cu(OH)2 + Na2SO4
m(NaOH) = 200*0,1 = 20 г
n(NaOH) = 20 / 40 = 0.5 моль
n(Cu(OH)2) = 1/2n(NaOH) = 0,5 / 2 = 0,25 моль
m(Cu(OH)2 = 0,25 * 98 = 24,5 г
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Answers & Comments
Verified answer
2NaOH + CuSO4 = Cu(OH)2 + Na2SO4m(NaOH) = 200*0,1 = 20 г
n(NaOH) = 20 / 40 = 0.5 моль
n(Cu(OH)2) = 1/2n(NaOH) = 0,5 / 2 = 0,25 моль
m(Cu(OH)2 = 0,25 * 98 = 24,5 г