СРОЧНО ПОМОГИТЕ С АЛЕГЕБРОЙ ООЧЕЕННЬ НАДО Преобразуйте выражение (y+2)^(3)

uldanovkamil116 @uldanovkamil116

July 2022 1 15 Report

СРОЧНО ПОМОГИТЕ С АЛЕГЕБРОЙ ООЧЕЕННЬ НАДО
Преобразуйте выражение
(y+2)^(3) - (y-2)^(2) + 0,2 (y+1) (1-y)

в фото №1 - б

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NNNLLL54

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Ответ:

$1a)\ \ 2(x-3)^2+5(x-4)(x+4)-(x+1)^3=\\\\=2(x^2-6x+9)+5(x^2-16)-(x^3+3x^2+3x+1)=\\\\=-x^3+(2+5-3)x^2+(-6\cdot 2-3)x+(9\cdot 2-80-1)=\\\\=-x^3+4x^2-15x-63\\\\b)\ \ (y+2)^3-(y-2)^2+0,2(y+1)(1-y)=\\\\=y^3+6y^2+12y+8-(y^2-4y+4)-0,2(1-y^2)=\\\\=y^3+5,2y^2+16y+3,8\\\\\\2a)\ \ 17^2-\underbrace{34}_{2\cdot 17}\cdot 7+7^2=17^2-2\cdot 17\cdot 7+7^2=(17-7)^2=10^2=100\\\\b)\ \ \dfrac{67^2-33^2}{15^2-25}=\dfrac{(67-33)(67+33)}{(15-5)(15+5)}=\dfrac{34\cdot 100}{10\cdot 30}=\dfrac{34}{3}=11\dfrac{1}{3}$

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