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olivin
@olivin
July 2022
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Срочно помогите! См. во вложении: нужно 5,1,2
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udodovi
5)
2моль хг
CH2NH2COOH+CH3OH = CH2NH2COOCH3
1моль 32г
х= 2*32/1=64г m (CH3OH) в-ва
m(CH3OH) р-ра = м в-ва *100%/ω=64*100%/90%=71,11г
V=m/ρ
V(CH3OH)= 71,11г/0,8г/см³=88,88см³
1) прикрепила
хг 6г
2) CH2NH2COOH+NaOH=CH2NH2COONa + H2O
75г 40г
м в-ва (NaOH)= м р-ра *ω/100%= 120*5%/100%=6г
х= 75*6/40=11,25г
2 votes
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Answers & Comments
2моль хг
CH2NH2COOH+CH3OH = CH2NH2COOCH3
1моль 32г
х= 2*32/1=64г m (CH3OH) в-ва
m(CH3OH) р-ра = м в-ва *100%/ω=64*100%/90%=71,11г
V=m/ρ
V(CH3OH)= 71,11г/0,8г/см³=88,88см³
1) прикрепила
хг 6г
2) CH2NH2COOH+NaOH=CH2NH2COONa + H2O
75г 40г
м в-ва (NaOH)= м р-ра *ω/100%= 120*5%/100%=6г
х= 75*6/40=11,25г