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Ruslan132
@Ruslan132
August 2022
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Срочно помогите упростите выражение 2sin^2x+3+2ctg^2x*sin^2x
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marasan7
2sin^2x+3+2ctg^2x*sin^2x = 5, т.к. (ctg2x = cos2x/sin2x, sin^2x +cos
^2x = 1), то:
1) ctg^2x = cos^2x/sin^2x
2)
2ctg^2x*sin^2x =
2cos^2x/sin^2x * sin^2x =
2
cos
^2x
3) 2sin^2x + 2cos^2x + 3 = 2 * 1 + 3 = 5
1 votes
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Answers & Comments
1) ctg^2x = cos^2x/sin^2x
2) 2ctg^2x*sin^2x = 2cos^2x/sin^2x * sin^2x = 2cos^2x
3) 2sin^2x + 2cos^2x + 3 = 2 * 1 + 3 = 5