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MissKrash
@MissKrash
July 2021
2
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Срочно !!!Помогите,пожалуйста,пункт 3 и 4
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Lesben
3) Tak kak sin 45 = (odm.iz 2)/2 i cos 135= -(odm. iz 2)/2 ect
2,9.sin45/cos135 = -2,9
4)169ˇ(-2.log13 2)
= (13ˇ2)ˇ(-2.log 13 2) = 13ˇ(-4.log13 2) = 13ˇlog13 2ˇ-4=13ˇlog13 (1/16)
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sedinalana
3
2,9sin45/cos(90+45)=2,9sin45/(-sin45)=-2,9
4
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Answers & Comments
2,9.sin45/cos135 = -2,9
4)169ˇ(-2.log13 2)
= (13ˇ2)ˇ(-2.log 13 2) = 13ˇ(-4.log13 2) = 13ˇlog13 2ˇ-4=13ˇlog13 (1/16)
2,9sin45/cos(90+45)=2,9sin45/(-sin45)=-2,9
4