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Sergo11111gsg
@Sergo11111gsg
August 2022
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Срочно пожалуйста, выручите))
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Anny00001
X²-2px+p²-1=0
∆=(-2p)²-4(1x(p-1))
∆=4p²-4p-4
∆=4(p²-p-1)
-(-2p)+(-2)√(p²-p-1)/2*1
2p+(-2)√(p²-p-1)/2=o
(-2)√(p²-p-1))²=(-2p)²
4(p²-2p-1)=4p²
4p²-8p-1=4p²
-8p-1=0
p=(-1)/8
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Answers & Comments
∆=(-2p)²-4(1x(p-1))
∆=4p²-4p-4
∆=4(p²-p-1)
-(-2p)+(-2)√(p²-p-1)/2*1
2p+(-2)√(p²-p-1)/2=o
(-2)√(p²-p-1))²=(-2p)²
4(p²-2p-1)=4p²
4p²-8p-1=4p²
-8p-1=0
p=(-1)/8