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Александр3335
@Александр3335
June 2022
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срочно пожалуста подробно
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fizzjer
1) 1+cosx не = 0
cosx не = -1
х не = π + 2πk (k∈Z)
2) 2cos2х*sin2x = 0
cos2x = 0 или sin2x = 0
а) 2х = πn/2 (n∈Z)
х = πn/4 (n∈Z)
б) 2х = πm (m∈Z)
x = πm/2 (m∈Z)
Ответ: πn/4 (n∈Z) и πm/2 (m∈Z)
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Answers & Comments
cosx не = -1
х не = π + 2πk (k∈Z)
2) 2cos2х*sin2x = 0
cos2x = 0 или sin2x = 0
а) 2х = πn/2 (n∈Z)
х = πn/4 (n∈Z)
б) 2х = πm (m∈Z)
x = πm/2 (m∈Z)
Ответ: πn/4 (n∈Z) и πm/2 (m∈Z)