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Ak1se
@Ak1se
August 2022
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Срочно! Рассчитать маccу хлора полученного из 9 грамм hcl
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mesnezok
M (HCL) = 9 g
n (HCL) = m/M = 9 g / 36,5 g/mol = 0,2466 mol
HCL ⇒ H + CL
n (HCL) = n (CL)
m (CL) = n (CL) * M = 0,2466 mol * 35,5 g/mol ≈ 8,8 g
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Answers & Comments
n (HCL) = m/M = 9 g / 36,5 g/mol = 0,2466 mol
HCL ⇒ H + CL
n (HCL) = n (CL)
m (CL) = n (CL) * M = 0,2466 mol * 35,5 g/mol ≈ 8,8 g