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NastiSeeu
@NastiSeeu
July 2022
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Срочно!!! Решить уравнение до конца
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sedinalana
(y-5)/(y-3)+4/(y+3)=24(y-3)(y+3)
(y-3)(y+3)≠0⇒y≠3;y≠-3
(y-5)(y+3)+4(y-3)=24
y²+3y-5y-15+4y-12-24=0
y²+2y-51=0
D=4+204=208
√D=4√13
y1=(-2-4√13)/2=-1-2√13 U y2=-1+2√13
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Answers & Comments
(y-3)(y+3)≠0⇒y≠3;y≠-3
(y-5)(y+3)+4(y-3)=24
y²+3y-5y-15+4y-12-24=0
y²+2y-51=0
D=4+204=208
√D=4√13
y1=(-2-4√13)/2=-1-2√13 U y2=-1+2√13