5.
ΔBCD∞ΔBAC (подобны), по двум углам, ⇒ BC/AB = BD/BC,
BC/(18+32) = 18/BC, ⇒BC²=50*18=900, BC=30/
CD=√BC²-BD²=√900-324=√576=24/
CA=√2500-900=√1600=40
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Answers & Comments
5.
ΔBCD∞ΔBAC (подобны), по двум углам, ⇒ BC/AB = BD/BC,
BC/(18+32) = 18/BC, ⇒BC²=50*18=900, BC=30/
CD=√BC²-BD²=√900-324=√576=24/
CA=√2500-900=√1600=40