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blackplaycrazy5
@blackplaycrazy5
July 2022
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!СРОЧНО! Решите пожалуйста 5 или 6, без разницы! даю 50 БАЛЛОВ
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OblivionFire
5.
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nafanya2014
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5.
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По условию
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5.![1)~~b_3=b_1\cdot q^2=18~;\\b_6=b_1\cdot q^5=486\Rightarrow\\\dfrac{b_6}{b_3}=\dfrac{b_1q^5}{b_1q^2}=q^3\Rightarrow\\q^3=\dfrac{486}{18}=27\Rightarrow\\q^3=27\Rightarrow q^3=3^3~;\\q=\sqrt[3]{3^3} =3. ~~OTVET~:~q=3.\\2)~~~ b_m=b_kq^{m-k}\Rightarrow q^{m-k}=\dfrac{b_m}{b_k} ~;\\q^{8-6}=\dfrac{b_8}{b_6} \Rightarrow q^2=\dfrac{9}{49} \Leftrightarrow q=\pm\dfrac{3}{7} .\\OTVET~:~q=\pm\dfrac{3}{7} .](https://tex.z-dn.net/?f=1%29~~b_3%3Db_1%5Ccdot%20q%5E2%3D18~%3B%5C%5Cb_6%3Db_1%5Ccdot%20q%5E5%3D486%5CRightarrow%5C%5C%5Cdfrac%7Bb_6%7D%7Bb_3%7D%3D%5Cdfrac%7Bb_1q%5E5%7D%7Bb_1q%5E2%7D%3Dq%5E3%5CRightarrow%5C%5Cq%5E3%3D%5Cdfrac%7B486%7D%7B18%7D%3D27%5CRightarrow%5C%5Cq%5E3%3D27%5CRightarrow%20q%5E3%3D3%5E3~%3B%5C%5Cq%3D%5Csqrt%5B3%5D%7B3%5E3%7D%20%3D3.%20~~OTVET~%3A~q%3D3.%5C%5C2%29~~~%20b_m%3Db_kq%5E%7Bm-k%7D%5CRightarrow%20q%5E%7Bm-k%7D%3D%5Cdfrac%7Bb_m%7D%7Bb_k%7D%20~%3B%5C%5Cq%5E%7B8-6%7D%3D%5Cdfrac%7Bb_8%7D%7Bb_6%7D%20%5CRightarrow%20q%5E2%3D%5Cdfrac%7B9%7D%7B49%7D%20%5CLeftrightarrow%20q%3D%5Cpm%5Cdfrac%7B3%7D%7B7%7D%20.%5C%5COTVET~%3A~q%3D%5Cpm%5Cdfrac%7B3%7D%7B7%7D%20. "1)~~b_3=b_1\cdot q^2=18~;\\b_6=b_1\cdot q^5=486\Rightarrow\\\dfrac{b_6}{b_3}=\dfrac{b_1q^5}{b_1q^2}=q^3\Rightarrow\\q^3=\dfrac{486}{18}=27\Rightarrow\\q^3=27\Rightarrow q^3=3^3~;\\q=\sqrt[3]{3^3} =3. ~~OTVET~:~q=3.\\2)~~~ b_m=b_kq^{m-k}\Rightarrow q^{m-k}=\dfrac{b_m}{b_k} ~;\\q^{8-6}=\dfrac{b_8}{b_6} \Rightarrow q^2=\dfrac{9}{49} \Leftrightarrow q=\pm\dfrac{3}{7} .\\OTVET~:~q=\pm\dfrac{3}{7} .")