Ответ:
1) ∠ABC=(360°-120°) : 2 = 120°
2) ∠BCD=∠BCA+∠ACD= 20° + 90° = 110°
3) ∪ АВ=2*40°=80° , ∪СD=2*20°=40° , ∪AD=180° ,
∪BC=180°-80°-40°=60° , ∠BAC=60°^2=30°
4) ∠АВC=2*30°=60° ⇒ ∠АОС=120° ⇒ ∪ADC=120° ,
∪ABC=360°-120°=240° ⇒ ∠ADC=240°^2=120°
5) ∠ВАС=∠ВЕС=20° ,
ΔADC: ∠ACD=90° ⇒ ∠CAD=90°-60°=30° ,
∠BAD=∠CAD+∠BAC=30°+20°=50°
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Verified answer
Ответ:
1) ∠ABC=(360°-120°) : 2 = 120°
2) ∠BCD=∠BCA+∠ACD= 20° + 90° = 110°
3) ∪ АВ=2*40°=80° , ∪СD=2*20°=40° , ∪AD=180° ,
∪BC=180°-80°-40°=60° , ∠BAC=60°^2=30°
4) ∠АВC=2*30°=60° ⇒ ∠АОС=120° ⇒ ∪ADC=120° ,
∪ABC=360°-120°=240° ⇒ ∠ADC=240°^2=120°
5) ∠ВАС=∠ВЕС=20° ,
ΔADC: ∠ACD=90° ⇒ ∠CAD=90°-60°=30° ,
∠BAD=∠CAD+∠BAC=30°+20°=50°