Ответ:min:=0;
for i:=1 to n do
readln(x);
if (min = 0) and (x mod 3 = 0) then
min:=x
else if (x < min) and (x mod 3 = 0) then
min:=x;
Объяснение:
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Answers & Comments
Ответ:min:=0;
for i:=1 to n do
readln(x);
if (min = 0) and (x mod 3 = 0) then
min:=x
else if (x < min) and (x mod 3 = 0) then
min:=x;
Объяснение: