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1612001
@1612001
September 2021
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срочно решите задачу по химии
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dietel
Cu(OH)+H2SO4>2H2O+CuSO4
---X-----------27г-----X---------X---
n(H2SO4)=M/m=2+32+16*4/27=98/27=3,6 моль
m(CuSO4)=n/M=63,5+32+16*4/3,6=159,5/3,6=44/3 г
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1612001
спасибо большое, очень выручили)))
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Answers & Comments
---X-----------27г-----X---------X---
n(H2SO4)=M/m=2+32+16*4/27=98/27=3,6 моль
m(CuSO4)=n/M=63,5+32+16*4/3,6=159,5/3,6=44/3 г