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sawed
@sawed
July 2022
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СРОЧНО РЕШИТЕ,ПОЖАЛУЙСТА!
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sangers1959
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13) ∫²₁(4x³+2x)dx=x⁴+x² |²₁=16+4-(1+1)=18.
14. ∫¹₋₁(6x³-5x)dx=(6/4)x⁴-(5/2)x² |¹₋₁=(3/2)*1⁴-(5/2)*1²-((3/2)*(-1)⁴-%/2)*(-1)²=0.
15. ∫π/₈ ₀(36/cos(2x)^2)dx=36*tg(2x)/2=18*tg(π/4)-18*tg0°=18*1-0=18.
16. ∫π/₂ ₀(2*sin(x)dx=-2*cos(x) |π/₂ ₀=-2*0-(-2*cos(π/2)=0+2*1=2.
17 ∫²₋₂(4-x^4)=(4x-x^5/5) |²₋₂=4*2-32/5-(4/(-2)-(-2)⁵/5=8/5+8/5=16/5=3,2.
18. ∫⁴₁x³=x⁴/4 |⁴₁=256/4-1/4=255/4=63³/₄.
19. ∫²/³₋₂/₃(3x³-2x)dx=3x⁴/4-x² |²/³₋₂/₃=3(2/3)⁴+(2/3)²-(3(-2/3)0⁴-(-2/3)²)=0.
20.∫⁰₋₃π cos(3x)dx=sin(3x) |⁰₋₃π=0-0=0.
21. ∫²π ₀ (cos(x/4)dx=sin(x/4)/(1/4) |²π ₀=4sin(x/4) |²π ₀=4*1-0=4.
22. ⁴₁(x²+9)=3x³/3+9x |⁴₁=4³/3+9*4-(1³/3+9*1)=48.
23. ∫²₋₁ 3x²dx =x³ |²₋₁=2³-(-1)³=9.
24. ∫⁰₋₁(1-2x)⁴dx=((1-2x)⁵/5)/(-2)=-(1-2x)⁵/10=
=-1⁵/10+((1-(-1)*2)⁵)/10)=-1/10+243/10=242/10=121/5=24,2.
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sawed
а дальше?
sawed
а можешь еще немного помочь?
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Answers & Comments
Verified answer
13) ∫²₁(4x³+2x)dx=x⁴+x² |²₁=16+4-(1+1)=18.14. ∫¹₋₁(6x³-5x)dx=(6/4)x⁴-(5/2)x² |¹₋₁=(3/2)*1⁴-(5/2)*1²-((3/2)*(-1)⁴-%/2)*(-1)²=0.
15. ∫π/₈ ₀(36/cos(2x)^2)dx=36*tg(2x)/2=18*tg(π/4)-18*tg0°=18*1-0=18.
16. ∫π/₂ ₀(2*sin(x)dx=-2*cos(x) |π/₂ ₀=-2*0-(-2*cos(π/2)=0+2*1=2.
17 ∫²₋₂(4-x^4)=(4x-x^5/5) |²₋₂=4*2-32/5-(4/(-2)-(-2)⁵/5=8/5+8/5=16/5=3,2.
18. ∫⁴₁x³=x⁴/4 |⁴₁=256/4-1/4=255/4=63³/₄.
19. ∫²/³₋₂/₃(3x³-2x)dx=3x⁴/4-x² |²/³₋₂/₃=3(2/3)⁴+(2/3)²-(3(-2/3)0⁴-(-2/3)²)=0.
20.∫⁰₋₃π cos(3x)dx=sin(3x) |⁰₋₃π=0-0=0.
21. ∫²π ₀ (cos(x/4)dx=sin(x/4)/(1/4) |²π ₀=4sin(x/4) |²π ₀=4*1-0=4.
22. ⁴₁(x²+9)=3x³/3+9x |⁴₁=4³/3+9*4-(1³/3+9*1)=48.
23. ∫²₋₁ 3x²dx =x³ |²₋₁=2³-(-1)³=9.
24. ∫⁰₋₁(1-2x)⁴dx=((1-2x)⁵/5)/(-2)=-(1-2x)⁵/10=
=-1⁵/10+((1-(-1)*2)⁵)/10)=-1/10+243/10=242/10=121/5=24,2.