Ответ:
(2a+3)(5a−1)+(a−1)(6a+5)=10a2−2a+15a−3+6a2+5a−6a−5==16a2+12a−8
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Ответ:
(2a+3)(5a−1)+(a−1)(6a+5)=10a2−2a+15a−3+6a2+5a−6a−5==16a2+12a−8