Alexei78
Дано m(ppaFe(OH)3)=755.3 g W=15% -------------------- m(fe2O3)-? m(Fe(OH)3) = 755.3*15%/100% = 113.3 g 113.3 X 2Fe(OH)3-->Fe2O3+3H2O M(Fe(OH)3)=107 g/mol , M(Fe2O3)=160 g/mol 2*107 160 X=113.3*160 / 214 = 84.71 g ответ 84.71 г
15. дано V(возд)=71.4 L NH3 ------------------ V(NO)-? V(H2O)-? V(O2)= 71.4*21% / 100%= 15 L 15 X Y 4NH3+5O2-->4NO+6H2O 5mol 4mol 6mol X(NO)=15*4 / 5 = 12 L Y(H2O) = 15*6/5=18 L ответ 12 л - NO 18 л--H2O
Answers & Comments
m(ppaFe(OH)3)=755.3 g
W=15%
--------------------
m(fe2O3)-?
m(Fe(OH)3) = 755.3*15%/100% = 113.3 g
113.3 X
2Fe(OH)3-->Fe2O3+3H2O M(Fe(OH)3)=107 g/mol , M(Fe2O3)=160 g/mol
2*107 160
X=113.3*160 / 214 = 84.71 g
ответ 84.71 г
15.
дано
V(возд)=71.4 L
NH3
------------------
V(NO)-?
V(H2O)-?
V(O2)= 71.4*21% / 100%= 15 L
15 X Y
4NH3+5O2-->4NO+6H2O
5mol 4mol 6mol
X(NO)=15*4 / 5 = 12 L
Y(H2O) = 15*6/5=18 L
ответ 12 л - NO 18 л--H2O