Ответ:
f
′
(x
0
)=u
)v(x
)+v
)u(x
)
f'(x_{0} )=(-3*-2)+(-4*3)=-6f
)=(−3∗−2)+(−4∗3)=−6
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Ответ:
f
′
(x
0
)=u
′
(x
0
)v(x
0
)+v
′
(x
0
)u(x
0
)
f'(x_{0} )=(-3*-2)+(-4*3)=-6f
′
(x
0
)=(−3∗−2)+(−4∗3)=−6