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Murrrrrk
@Murrrrrk
July 2022
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СРОЧНО!!!!866 И 865!!!!!!
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DyzZy
Пусть x,y,z -числа монет каждого достоинства.
5x+20y+50z=500
x+y+z=20
x+4y+10z=100
x+y+z=20
Вычтем уравнения:
3y+9z=80
3*(y+3z)=80
Но 80 не делиться на 3.
Ответ:невозможно.
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Answers & Comments
5x+20y+50z=500
x+y+z=20
x+4y+10z=100
x+y+z=20
Вычтем уравнения:
3y+9z=80
3*(y+3z)=80
Но 80 не делиться на 3.
Ответ:невозможно.