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Liza197867
@Liza197867
August 2022
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Выполните действие . 4b^2+(3a+2b)(3a+3b)
разложите на множители а^6+b^6
решите уравнения 1-(1-х)^2=0.
/срочно
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litanalove
4b² +(3a +2b)(3a +3b) =4b² +9a² +9ab +6ab +6b² =9a² +15ab +10b²
a^6 +b^6 =(a² +b²)(a^4 -a²b² +b^4)
1 -(1 -x)² =0
1 -(1 -2x +x²) =0
1 -1 +2x -x² =0
2x -x² =0
x(2 -x) =0
x =0
2 -x =0
-x = -2
x =2
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Answers & Comments
a^6 +b^6 =(a² +b²)(a^4 -a²b² +b^4)
1 -(1 -x)² =0
1 -(1 -2x +x²) =0
1 -1 +2x -x² =0
2x -x² =0
x(2 -x) =0
x =0
2 -x =0
-x = -2
x =2