О(2; 1), r=3 ←→ х=2; у=1 →
→ (х-2)² + (у-1)² = 3² →
→ центр (2; 1), r = 3.
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
О(2; 1), r=3 ←→ х=2; у=1 →
→ (х-2)² + (у-1)² = 3² →
→ центр (2; 1), r = 3.