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bogdan1263
@bogdan1263
July 2022
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Срочнооо помогите решить 1+sin2L-cos2L
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sedinalana
1 + Sin2α - Cos2α = 1 + Sin2α - ( 1 - 2Sin²α) = 1 + 2SinαCosα - 1 + 2Sin²α =
= 2SinαCosα + 2Sin²α = 2Sinα(Cosα + Sinα)
1 votes
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Universalka
Verified answer
(1-cos2L)+sin2L=2sin²L+2sinLcosL=2sinL(sinL+cosL)
3 votes
Thanks 2
армения20171
можно и так 1-(cos2L-sin2L)=1-√2*sin(π/4+2L)
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Answers & Comments
= 2SinαCosα + 2Sin²α = 2Sinα(Cosα + Sinα)
Verified answer
(1-cos2L)+sin2L=2sin²L+2sinLcosL=2sinL(sinL+cosL)