• Оксид серы (Ⅳ) — SO₂.Mᵣ(SO₂) = Aᵣ(S) + 2Aᵣ(O) = 32 + 2*16 = 32 + 32 = 64.Ответ : ω(S) = 50%, ω(O) = 50%. • Оксид серы (Ⅵ) — SO₃.Mᵣ(SO₃) = Aᵣ(S) + 3Aᵣ(O) = 32 + 3*16 = 32 + 48 = 80.Ответ : ω(S) = 40%, ω(O) = 60%.
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• Оксид серы (Ⅳ) — SO₂.




Mᵣ(SO₂) = Aᵣ(S) + 2Aᵣ(O) = 32 + 2*16 = 32 + 32 = 64.
Ответ : ω(S) = 50%, ω(O) = 50%.
• Оксид серы (Ⅵ) — SO₃.
Mᵣ(SO₃) = Aᵣ(S) + 3Aᵣ(O) = 32 + 3*16 = 32 + 48 = 80.
Ответ : ω(S) = 40%, ω(O) = 60%.