5)

1) при Q< 0 ΔH₂₉₈ > 0

6)

дано

m(H2O) = 182 g

n(C6H12O6) = 0.1 mol

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W(C6H12O6)-?

M(C6H12O6) = 180 g/mol

m(C6H12O6) = n*M = 0.1*180 = 18 g

W(C6H12O6) = m(C6H12O6) / (m(H2O + m(C6H12O6)) * 100%

W(C6H12O6) = 18 / (182+18) / 100% = 9%

ответ 9%