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anastachka
@anastachka
March 2022
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Срооооочно,ХИМИЯ ДАЮ 25 Б
решите,пожалуйста,номер4
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Кляксус
2NaOH + CuSO4 = Cu(OH)2 + Na2SO4
m (NaOH) = m (р-ра) * ω = 200 * 0,1 = 20 г
n (NaOH) = m : M = 20 : (23 + 16 + 1) = 0,5 моль
n (Cu(OH)2) = 0,5n (NaOH) = 0,25 моль
m (Cu(OH)2) = n * M = 0,25 * (64 + 2(16 + 1)) = 24,5 г
Ответ: m (Cu(OH)2) = 24,5 г
1 votes
Thanks 1
anastachka
А почему n(cu(on)2) получилось равно 0.25?
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Answers & Comments
m (NaOH) = m (р-ра) * ω = 200 * 0,1 = 20 г
n (NaOH) = m : M = 20 : (23 + 16 + 1) = 0,5 моль
n (Cu(OH)2) = 0,5n (NaOH) = 0,25 моль
m (Cu(OH)2) = n * M = 0,25 * (64 + 2(16 + 1)) = 24,5 г
Ответ: m (Cu(OH)2) = 24,5 г