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reginakurbanov
@reginakurbanov
November 2021
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сторона ромба равна 10 дм а его тупой угол равен 150 градусов найдите площадь ромба
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sinusoida2000
Verified answer
∠В=150
∠А=180-∠В=30
АВ=10
S=AB^2*sina=100*sin30=100/2=50
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SerGreyVXXX211
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Answers & Comments
Verified answer
∠В=150∠А=180-∠В=30
АВ=10
S=AB^2*sina=100*sin30=100/2=50