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panda833
@panda833
November 2021
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Струм в паяльнику 500 мА. Яка кiлькiсть електрики пройде через паяльник за 2 хв.
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DimR97
Дано:
I = 500mA=0.5A
t=2мин=120с
Решение:
I=q/t
q=It=0.5*120=60Кл
17 votes
Thanks 48
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Answers & Comments
I = 500mA=0.5A
t=2мин=120с
Решение:
I=q/t
q=It=0.5*120=60Кл