студент знает 30 из 40 вопросов программы. в билете содержится три вопроса. найти вероятность того, что :
а) студент знает ответ на все три вопроса
б)только на два вопроса
в)хотя бы на два вопроса.
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a)![p_a=\frac{C_{30}^3*C_{10}^0}{C_{40}^3}=\frac{30!}{27!*3!}*\frac{10!}{10!0!}:\frac{40!}{37!*3!}=\frac{28*29*30}{38*39*40}=\frac{203}{494}\approx0.41 p_a=\frac{C_{30}^3*C_{10}^0}{C_{40}^3}=\frac{30!}{27!*3!}*\frac{10!}{10!0!}:\frac{40!}{37!*3!}=\frac{28*29*30}{38*39*40}=\frac{203}{494}\approx0.41](https://tex.z-dn.net/?f=p_a%3D%5Cfrac%7BC_%7B30%7D%5E3%2AC_%7B10%7D%5E0%7D%7BC_%7B40%7D%5E3%7D%3D%5Cfrac%7B30%21%7D%7B27%21%2A3%21%7D%2A%5Cfrac%7B10%21%7D%7B10%210%21%7D%3A%5Cfrac%7B40%21%7D%7B37%21%2A3%21%7D%3D%5Cfrac%7B28%2A29%2A30%7D%7B38%2A39%2A40%7D%3D%5Cfrac%7B203%7D%7B494%7D%5Capprox0.41)
b)![p_b=\frac{C_{30}^2*C_{10}^1}{C_{40}^3}=\frac{30!}{28!2!}*\frac{10!}{9!1!}:\frac{40!}{37!3!}=\frac{29*30*10*2*3}{2*38*39*40}=\frac{435}{988}\approx0.44 p_b=\frac{C_{30}^2*C_{10}^1}{C_{40}^3}=\frac{30!}{28!2!}*\frac{10!}{9!1!}:\frac{40!}{37!3!}=\frac{29*30*10*2*3}{2*38*39*40}=\frac{435}{988}\approx0.44](https://tex.z-dn.net/?f=p_b%3D%5Cfrac%7BC_%7B30%7D%5E2%2AC_%7B10%7D%5E1%7D%7BC_%7B40%7D%5E3%7D%3D%5Cfrac%7B30%21%7D%7B28%212%21%7D%2A%5Cfrac%7B10%21%7D%7B9%211%21%7D%3A%5Cfrac%7B40%21%7D%7B37%213%21%7D%3D%5Cfrac%7B29%2A30%2A10%2A2%2A3%7D%7B2%2A38%2A39%2A40%7D%3D%5Cfrac%7B435%7D%7B988%7D%5Capprox0.44)
c)![p_c=p_a+p_b=0.41+0.44=0.85 p_c=p_a+p_b=0.41+0.44=0.85](https://tex.z-dn.net/?f=p_c%3Dp_a%2Bp_b%3D0.41%2B0.44%3D0.85)