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diankalazovska
@diankalazovska
May 2021
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сумма первых 10 членов арифметической прогрессии равна 5,а сумма первых 40 равна 80 .Найти сумму 20 первых членов
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mukus13
Verified answer
S10=(2a+9d)*10/2=(2a1+9d)*5=5
2a1+9d=1
S40=(2a1+39d)*40/2=(2a1+39d)*20=80
2a1+39d=4
Отнимем
30d=3
d=3/30=0,1
2a1=1-9*0,1=1-0,9=0,1
a1=0,1:2=0,05
S20=(2a1+19d)*20/2=(2a1+19d)*10=(0,1+1,9)*20=2*20=40
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Answers & Comments
Verified answer
S10=(2a+9d)*10/2=(2a1+9d)*5=52a1+9d=1
S40=(2a1+39d)*40/2=(2a1+39d)*20=80
2a1+39d=4
Отнимем
30d=3
d=3/30=0,1
2a1=1-9*0,1=1-0,9=0,1
a1=0,1:2=0,05
S20=(2a1+19d)*20/2=(2a1+19d)*10=(0,1+1,9)*20=2*20=40