Свернуть по формуле разность квадратов:
1) (5-k)(5+k)=
2)(7-3a)(7+3a)=
3)(4-8p)(4+8p)=
4)(1-4y)(1+4y)=
5(9y-5p)(9y+5p)=
1) (5-k)(5+k)=
2)(7-3a)(7+3a)=
3)(4-8p)(4+8p)=
4)(1-4y)(1+4y)=
5(9y-5p)(9y+5p)=
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Answers & Comments
2)(7 - 3a)(7 + 3a) = 49 - 9a²
3)(4 - 8p)(4 + 8p) = 16 - 64p²
4)(1 - 4y)(1 + 4y) = 1 - 16y²
5)(9y - 5p)(9y + 5p) = 81y² - 25p²
Verified answer
1)25-k^22)49-9a^2
3)16-64p^2
4)1-16y^2
5)81y^2-25p^2