дано
m(P) = 5 g
-------------------
V(O2)-?
4Р+5О2→2Р2О5
M(P) = 31 g/mol
n(P) = m/M = 5/ 31 = 0.16 mol
4n(P) = 5n(O2)
n(O2) = 5*0.16 / 4 = 0.2 mol
V(O2) = n(O2)*Vm = 0.2 * 22.4 = 4.48 L
ответ Не хватит
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Answers & Comments
дано
m(P) = 5 g
-------------------
V(O2)-?
4Р+5О2→2Р2О5
M(P) = 31 g/mol
n(P) = m/M = 5/ 31 = 0.16 mol
4n(P) = 5n(O2)
n(O2) = 5*0.16 / 4 = 0.2 mol
V(O2) = n(O2)*Vm = 0.2 * 22.4 = 4.48 L
ответ Не хватит