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ilyakozlow200
@ilyakozlow200
July 2022
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alishady99
M(Na2CO3 • 10H2O)= 143г
m (Na2CO3 ) = 102× 143 ÷ 282 =51.7г
5% - 51.7г
100% - х= 1034г
m(H2O)=1034г - 143г = 891г
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Answers & Comments
m (Na2CO3 ) = 102× 143 ÷ 282 =51.7г
5% - 51.7г
100% - х= 1034г
m(H2O)=1034г - 143г = 891г