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Fairell
@Fairell
July 2022
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Техническая механика
2 и 4 задачи решите
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improoove
2) ω=v/r
ω=0,4π/0,1=4π
ω=2πν => ν=2об/с=120об/мин
4)Закон сохранения энергии
mgh=mv²/2
v=√2gh=√2*10*3,2=8м/с
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Answers & Comments
ω=0,4π/0,1=4π
ω=2πν => ν=2об/с=120об/мин
4)Закон сохранения энергии
mgh=mv²/2
v=√2gh=√2*10*3,2=8м/с