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OLEN6KA
@OLEN6KA
August 2022
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тело движется по закону s(t)=2x^2-x
Найдите в какой момент тело остановится
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kirichekov
Verified answer
S'(t)=v(t)
s'(t)=(2t²-t)'=4t-1
v(t)=0 (по условию: тело остановится)
4t-1=0
t=1/4,
t=0,25
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Answers & Comments
Verified answer
S'(t)=v(t)s'(t)=(2t²-t)'=4t-1
v(t)=0 (по условию: тело остановится)
4t-1=0
t=1/4, t=0,25