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dasha1001
@dasha1001
June 2022
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Тело свободно падает с высоты 80 м. Каково его перемещение в последнюю секунду падения?
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MashaPutnaj
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H=80 м Δh- ?
h=g*t²/2
t=√2*h/g=√160/10=4 с
h1=g*t1²/2=10*9/2=45 м
Δh=80-45=35 м
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Answers & Comments
Verified answer
H=80 м Δh- ?h=g*t²/2
t=√2*h/g=√160/10=4 с
h1=g*t1²/2=10*9/2=45 м
Δh=80-45=35 м