Ответ:
1)
2)
3)
4)
5)
Объяснение:
1) (1 - cos a)(1 + cos a) = 1 -
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Answers & Comments
Ответ:
1)
2)
3)
4)
5)
Объяснение:
1) (1 - cos a)(1 + cos a) = 1 -
2)
3)
4)
5)