тема :применение непрерывности и производной
решите неравенство методом интервалов
дробь x²пи-3≤0
x-1
решите неравенство методом интервалов
дробь x²пи-3≤0
x-1
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(x-√(3/π))(x+√(3/π))/(x-1)≤0x=√(3/π) x=-√(3/π) x=1
_ + _ +
-------------[-√(3/π)]---------[√(3/π)]----------(1)----------------
x∈(-∞;-√(3/π)] U [√(3/π);1)