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aleno4katerman
@aleno4katerman
July 2022
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С1.
7[tex]sin^{2} x[/tex]+4sin x cos x-3[tex]cos^{2} x[/tex]= 0
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Answers & Comments
vivalaviva12
Сначала поделить всю эту *** на cos^2x
Получим:
7tg^2x + 4tgx - 3 = 0
Tgx = t
7t^2 + 4t -3 = 0
D = 16+84= 100
T1 = -4+10/14 = 3/7
T2 = -14/14 = -1
Tgx = 3/7
X = arctg3/7 + pn
Tgx = -1
X = -arctg1 + pn
X = -p/4 + pn
2 votes
Thanks 1
aleno4katerman
спасибо.
aleno4katerman
только ошибочка есть... если я сама не ошибаюсь... Т1=-4+10/7*2 (формула т1=-в*корень из дикриминанта/2а) ну это ничего страшно
aleno4katerman
ок, спасибо)
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Answers & Comments
Получим:
7tg^2x + 4tgx - 3 = 0
Tgx = t
7t^2 + 4t -3 = 0
D = 16+84= 100
T1 = -4+10/14 = 3/7
T2 = -14/14 = -1
Tgx = 3/7
X = arctg3/7 + pn
Tgx = -1
X = -arctg1 + pn
X = -p/4 + pn