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17катюха
@17катюха
May 2021
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[tex] \lim_{x \to \11 \frac{ x^{2} -1}{x-1} [/tex]
1)0
2)2
3)бесконечность
4)4
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hlopushinairina
Limx->1[(x²-1)/(x-1)]=0/0;
limx->1[(x²-1)/(x-1)=limx->1[(x-1)·(x+1)/(x-1)]=limx->1(x+1)=1+1=2
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limx->1[(x²-1)/(x-1)=limx->1[(x-1)·(x+1)/(x-1)]=limx->1(x+1)=1+1=2