Решите уравнение:x-[tex] \sqrt{x} [/tex]-12=0. Created by QzOrG. algebra-ru

Х√х = 12(x√x) = (x)^2(x) = (12)^2(x)^2(x) = 144x^2(x) = 144x^3 = 144x = x = 2* - Потому что х = => x = 2x ≈ 5.24

tex]-12=0...

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Решите уравнение:
x-[tex] \sqrt{x} [/tex]-12=0

Answers & Comments

Nesh1999 Х√х = 12
(x√x) $^{2}$ = $(12) ^{2}$
(x)^2(x) = (12)^2
(x)^2(x) = 144
x^2(x) = 144
x^3 = 144
x = $\sqrt[3]{144}$
x = 2* $\sqrt[3]{18}$ - Потому что х = $\sqrt[3]{2*2*2*18}$
=> x = 2 $2\sqrt[3]{18}$
x ≈ 5.24

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