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angelikamoore
@angelikamoore
June 2022
1
6
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Найти корни уравнений
[tex] \sqrt{56-2x} [/tex]=6
4/5х=23+1\5
х-43/х-5=3
[tex] x^{2} [/tex]+12х+32=0
2[tex] x^{2} [/tex]-13х+11=0
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teplovk
В первом уравнении ответ 10 во втором х=25 в третьем два корня -4+(59)^0.5 и -4-(59)^0.5 в четвертом два корня 4 и -8 в пятом два корня 6 и 1
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