Помогите решить.
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1. (y + 4)(4 - y) + (y + 5)y > 6y - 20
2. (3x + 2)[tex]^{2} [/tex] - (4 - 3x)[tex]^{2} [/tex] [tex] \leq [/tex] 14 + 37x
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--------------------------------------------------------------------------------------------------------
1. (y + 4)(4 - y) + (y + 5)y > 6y - 20
2. (3x + 2)[tex]^{2} [/tex] - (4 - 3x)[tex]^{2} [/tex] [tex] \leq [/tex] 14 + 37x
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Answers & Comments
Verified answer
116-y²+y²+5y-6y+20>0
y<36
y∈(-∞;36)
2
9x²+12x+4-16+24x-9x²-14-37x≤0
x≥-26
x∈[-26;∞)