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LiMinocenkova
@LiMinocenkova
July 2022
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найти первообразную , проходящую через точку
a) f(x)=6x-sinx M(0;5)
b) f(x)=sinx A([tex] \pi /2[/tex]; -1)
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kalbim
Verified answer
1) f(x)=6x-sinxF(x) = 6*(x^2 / 2) - (-cosx) + C = 3x^2 + cosx + CF=5, x=03*0 + cos(0) + C = 5, 1+C=5, C=5-1=4F(x) = 3x^2 + cosx + 4
2) f(x)=sinxF(x) = -cosx + CF=-1, x=pi/2-cos(pi/2) + C = -1
C=cos(pi/2) - 1 = 0-1=-1
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Answers & Comments
Verified answer
1) f(x)=6x-sinxF(x) = 6*(x^2 / 2) - (-cosx) + C = 3x^2 + cosx + CF=5, x=03*0 + cos(0) + C = 5, 1+C=5, C=5-1=4F(x) = 3x^2 + cosx + 42) f(x)=sinxF(x) = -cosx + CF=-1, x=pi/2-cos(pi/2) + C = -1C=cos(pi/2) - 1 = 0-1=-1