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LoliPeen
@LoliPeen
August 2022
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Найдите корень уравнения
1) 2[tex] x^{2} [/tex] -x = 0
2) [tex] y^{3} [/tex] - 21y = 0
3) 2[tex] k^{2} [/tex] - 16k = 0
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Verified answer
2х²-х=0,
х(2х-1)=0,
х=0, 2х-1=0,
2х=1,
х=1:2,
х=0,5.
Ответ: 0; 0,5.
у³-21у=0,
у(у²-21)=0,
у=0, у²-21=0,
у=√21,
у=-√21.
Ответ: -√21; 0; √21.
2k²-16k=0,
2k(k-8)=0,
2k=0, k-8=0,
k=0. k=8.
Ответ: 0; 8.
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Answers & Comments
Verified answer
2х²-х=0,х(2х-1)=0,
х=0, 2х-1=0,
2х=1,
х=1:2,
х=0,5.
Ответ: 0; 0,5.
у³-21у=0,
у(у²-21)=0,
у=0, у²-21=0,
у=√21,
у=-√21.
Ответ: -√21; 0; √21.
2k²-16k=0,
2k(k-8)=0,
2k=0, k-8=0,
k=0. k=8.
Ответ: 0; 8.