[tex] \frac{5x+14}{x^2-4} = \frac{x^2}{x^2-4} [/tex]
и еще [tex] \frac{8}{x-3} - \frac{10}{x} [/tex] = 2
и еще [tex] \frac{8}{x-3} - \frac{10}{x} [/tex] = 2
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х²-4 х²-4
х≠-2 х≠2
5х+14=х²
х²-5х-14=0
Д=25+4*14=25+56=81
х₁=5-9 = -4 = -2 - не подходит
2 2
х₂=14 = 7
2
Ответ: 7.
8 - 10 = 2
х-3 х
х≠0 х≠3
8х-10(х-3)=2х(х-3)
8х-10х+30=2х²-6х
2х²-4х-30=0
х²-2х-15=0
Д=4+60=64
х₁= 2-8 = -3
2
х₂= 5
Ответ: -3; 5.