Решите неравенство:
log[tex] {0,3} [/tex] (x-1) +log[tex] {0,3} [/tex] (x+1) > log[tex] {0,3} [/tex] (2x-1)
log[tex] {0,3} [/tex] (x-1) +log[tex] {0,3} [/tex] (x+1) > log[tex] {0,3} [/tex] (2x-1)
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log0.3((x-1)*(x+1))>log0.3(2x-1)
log0.3(x^2-1)>log0.3(2x-1)
x^2-1<2x-1
x принадлежит(0,2), x принадлежит(1,+бесконечность)