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Jassyby
@Jassyby
July 2022
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Является ли число 54,5 членом арифметической прогрессии ( [tex]a_{n} [/tex] ), в которой [tex]a_{1} [/tex] = 25,5 и [tex]a_{9} [/tex] = 5,5
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ShirokovP
Verified answer
A1 = 25,5
a9 = 5,5
a9 = a1 + 8d = 5,5
d = (5,5 - 25,5)/8 = -2,5
an = a1 + d(n - 1) = 54,5
25,5 - 2,5(n - 1) = 54,5
- 2,5n + 2,5 + 25,5 = 54,5
- 2,5n = 26,5
n не может быть отриц
не является
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Jassyby
спасибо большое
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Answers & Comments
Verified answer
A1 = 25,5a9 = 5,5
a9 = a1 + 8d = 5,5
d = (5,5 - 25,5)/8 = -2,5
an = a1 + d(n - 1) = 54,5
25,5 - 2,5(n - 1) = 54,5
- 2,5n + 2,5 + 25,5 = 54,5
- 2,5n = 26,5
n не может быть отриц
не является