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July 2022
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Найдите сумму абсцисс точек пересечения параболы у = [tex] 2x^{2} [/tex] – 5х + 2 с осью абсцисс.
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Vas61
2x²-5x+2=0
D=25-4·2·2=9
x₁=(5-3)/4=1/2=0,5
x₂=(5+3)/4=2
x₁+x₂=0,5+2=2,5
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Answers & Comments
D=25-4·2·2=9
x₁=(5-3)/4=1/2=0,5
x₂=(5+3)/4=2
x₁+x₂=0,5+2=2,5