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Artem1114
@Artem1114
July 2022
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Найти точку максимума функции y=ln[tex](x+5)^{2}[/tex]-5x
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sedinalana
Verified answer
Y`=[ln(x+5)²]`*[(x+5)²]`*(x+5)`-(5x)`=1/(x+5)² *2(x+5)*1-5=
=2/(x+5) -5
2/(x+5) -5=0
2/(x+5)=5
x+5=2/5
x=-5+0,4
x=-4,6
- + -
----------------(-5)-------------(-4,6)-------------------
min max
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Answers & Comments
Verified answer
Y`=[ln(x+5)²]`*[(x+5)²]`*(x+5)`-(5x)`=1/(x+5)² *2(x+5)*1-5==2/(x+5) -5
2/(x+5) -5=0
2/(x+5)=5
x+5=2/5
x=-5+0,4
x=-4,6
- + -
----------------(-5)-------------(-4,6)-------------------
min max