Объяснение:
√4,1 - √1,2 - √0,1 = √1/10(√41 - 2√3 - 1)
Ответ:
Будет [tex]\frac{\sqrt{410}-\sqrt{10} }{10} -\frac{\sqrt{30} }{5}[/tex]
[tex]\sqrt{4,1} -\sqrt{1,2} -\sqrt{0,1} =\\ \\ =\sqrt{\frac{41}{10} } -\sqrt{\frac{6}{5} } -\sqrt{\frac{1}{10} } =\\ \\ =\frac{\sqrt{41} }{\sqrt{10} }-\frac{\sqrt{6} }{\sqrt{5} } -\frac{1}{\sqrt{10} } =\\ \\ =\frac{\sqrt{410} }{10} -\frac{\sqrt{30} }{5} -\frac{\sqrt{10} }{10} =\\ \\ =\frac{\sqrt{410}-\sqrt{10} }{10} -\frac{\sqrt{30} }{5}[/tex]
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Объяснение:
√4,1 - √1,2 - √0,1 = √1/10(√41 - 2√3 - 1)
Ответ:
Будет [tex]\frac{\sqrt{410}-\sqrt{10} }{10} -\frac{\sqrt{30} }{5}[/tex]
Объяснение:
[tex]\sqrt{4,1} -\sqrt{1,2} -\sqrt{0,1} =\\ \\ =\sqrt{\frac{41}{10} } -\sqrt{\frac{6}{5} } -\sqrt{\frac{1}{10} } =\\ \\ =\frac{\sqrt{41} }{\sqrt{10} }-\frac{\sqrt{6} }{\sqrt{5} } -\frac{1}{\sqrt{10} } =\\ \\ =\frac{\sqrt{410} }{10} -\frac{\sqrt{30} }{5} -\frac{\sqrt{10} }{10} =\\ \\ =\frac{\sqrt{410}-\sqrt{10} }{10} -\frac{\sqrt{30} }{5}[/tex]